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x^2=650000
We move all terms to the left:
x^2-(650000)=0
a = 1; b = 0; c = -650000;
Δ = b2-4ac
Δ = 02-4·1·(-650000)
Δ = 2600000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2600000}=\sqrt{40000*65}=\sqrt{40000}*\sqrt{65}=200\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200\sqrt{65}}{2*1}=\frac{0-200\sqrt{65}}{2} =-\frac{200\sqrt{65}}{2} =-100\sqrt{65} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200\sqrt{65}}{2*1}=\frac{0+200\sqrt{65}}{2} =\frac{200\sqrt{65}}{2} =100\sqrt{65} $
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